72x^2-97.2x+29.16=0

Solution for 72x^2-97.2x+29.16=0 equation:

72x^2-97.2x+29.16=0

a = 72; b = -97.2; c = +29.16;
Δ = b2-4ac
Δ = -97.22-4·72·29.16
Δ = 1049.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-97.2)-\sqrt{1049.76}}{2*72}=\frac{97.2-\sqrt{1049.76}}{144}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-97.2)+\sqrt{1049.76}}{2*72}=\frac{97.2+\sqrt{1049.76}}{144}
$